Answers
A local boater's map shows a marker buoy 20 miles out in the ocean from the harbor at Woods Hole. Estimate the number of yards this distance is, (hint first round the number of yards in one mile to the nearest thousand yards, then finish the calcualtion)
1760 yards in one mile
2000 yards rounded to nearest thousand
2000 x 20 = 40,000
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A speedboat moving at 39.0 m/s approaches a no-wake buoy marker 100 m ahead. The pilot slows the boat with a constant acceleration of -3.35 m/s2 by reducing the throttle.
rehabilitated?
As long as they can stay away from the port.
Why do they call them all Bob?
with a constant acceleration of -2.7 m/s^2 by reducing the throttle.
How long does it take the boat to reach the buoy? Answer in units of seconds.
Thank you
Friend of mine went out on charter boat from Wild Winds Marina near power plant at Lake Erie. He claims it was only a 10minute ride and they fished for walleye outside of Kelly's Island. He said that the captain told him they were fishing around "K" and"L" Buoys. I know that there is no way it was only a 10 minute ride on water from around the power plant to kelly's Island. My friend said he could see the Roller Coasters at Cedar Point from the boat. I tried looking up Buoy markers on the internet for lake Erie and can't find any map to locate these buoys. Does anyone know the exact location of "K" and "L" Buoys at Lake Erie? I want to take a trip out on a "Walk on Party Boat" . If my friend is wrong about where he was fishing then I may be going to the wrong marina to catch a boat and get a really long boat ride.
Thank You
http://www.lake-erie-fishing.com/latlon.html
does camp perry range mean anythng to you?
A speedboat moving at 30.0 m/s approaches a no-wake buoy marker 100 m ahead. The pilot slows the boat with a constant acceleration of -3.8 m/s2 by reducing the throttle.
I need to find out how long it takes for the boat to get to the buoy and the velocity of the boat when it reaches the buoy. Thank you.
First working formula,
S = VT - (1/2)aT^2
where
S = distance of boat from buoy = 100 m
V = initial velocity of boat = 30 m/sec
T = time for boat to reach the buoy
a = acceleration = - 3.8 m/sec^2
Substituting values,
100 = 30T - (1/2)(3.8)T^2
100 = 30T - 1.9T^2
Rewriting the above,
1.9T^2 - 30T + 100 = 0
Using the quadratic formula,
T = 4.78 sec.
Next working formula is
Vf - Vo = aT
where
Vf = velocity of boat as it reaches the buoy
and all the other terms have been defined.
Substituting values,
Vf - 30 = (-3.8)(4.78)
Vf = 11.84 m/sec.
Hope this helps.
Surface Marker Buoys 25lb
Code Number:
SF-FDSMB1
Description:
Surface Marker Buoys 25lb.
Size:
150cm (5ft.)
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